Is there a way to determine the maximum inscribed circle within a particle count in Image-Pro 11?

Hi uaya,

If you want to create the circle manually, you can use Best-Fit circle tool.
If you want to get it automatically, you can use statistical table to get min/max values of object centroids and then draw the circle based on the bounding box of all objects from a macro.

Here is the macro that can draw the circle inscribing all objects inside:

Imports MediaCy.Addins.Measurements
Public Module Module1

    Public Sub CreateCountCircle
        Dim im As McImage=ThisApplication.ActiveImage
        If im Is Nothing Then Exit Sub
        Dim md As McMMData=im.MeasurementsData
        If md.Count=0 Then Exit Sub
        Dim pixSize As Double=1
        If im.SpatialCalibration IsNot Nothing Then
            'get pixel size of calibrated image
            pixSize=im.SpatialCalibration.PixelSizeX
        End If
        'get max/min of CentroidX and CentroidY
        Dim xmin As Double=md.Statistics(eMeasures.RgnCentroidX).Minimum
        Dim xmax As Double=md.Statistics(eMeasures.RgnCentroidX).Maximum
        Dim ymin As Double=md.Statistics(eMeasures.RgnCentroidY).Minimum
        Dim ymax As Double=md.Statistics(eMeasures.RgnCentroidY).Maximum
        'get average object diameter
        Dim dmean As Double=md.Statistics(eMeasures.RgnDiameterEq).Mean
        'calculate circle center in pixel coordinates
        Dim x As Double=((xmin+xmax)/2)/pixSize
        Dim y As Double=((ymin+ymax)/2)/pixSize
        'calculate diameter x and y
        Dim dx As Double=xmax-xmin
        Dim dy As Double=ymax-ymin
        'get Max radius on inscribed circle (including dmean)
        Dim r As Double=((System.Math.Max(dx,dy)+dmean)/2)/pixSize
        'draw circle
        Dim meas1
        With Measure.MeasurementsCommands.Add(Nothing)
            .MeasurementType = McMeasurements.enumMMSTypes.mmtsEllipse
            .Points = New System.Collections.Generic.List(Of System.Drawing.PointF)
            .Points.Add(New System.Drawing.PointF(x,y))
            .Points.Add(New System.Drawing.PointF(2*r,2*r))
            .Points.Add(New System.Drawing.PointF(0F,0F))
            .FeatureName = "Count Circle"
            .SnapFeature = False
            .Run(im, meas1)
        End With
    End Sub
End Module

The result will look like this:



Regards,

Yuri

Hi uaya,

Then I completely misunderstood your question. Measuring inscribed circle of every measured object is a different task.

There is no built-in measurement that provides this measure, but I will show you the steps how to get it using a Distance map. Distance map creates an image of the mask where pixel intensities are equal to the distance from the current pixel to the closest edge of the object, so measuring the Maximum Intensity of the distance map will give you the Radius of the Inscribed circle to that object, in pixels.

Here are the steps:
1. Create Mask of you objects using the Mask button

2. Create Distance Map of the mask image, use 3D Filters, as they produce a higher accuracy map:

3. Segment distance map using Threshold=1 and measure Intensity Max of each object - it corresponds to the Radius of the inscribed circle (in pixels)

4. Optionally, if your image is calibrated, you can create Intensity calibration that matches the spatial calibration, so Intensity Max will give you the Radius in Calibrated units (µm).

I've added an Inscribed Circle (C2) to the image, that illustrates that the Radius of the circle matches the Intensity Max of the object, in micrometers.

Yuri

Whoops, my last post was misleading.  The center of the inscribed circle would be the average of the two end-points of the minimum diameter line, which passes through the centroid but is not necessarily evenly balanced around it.  To find the end points of the minimum diameter line, you would need to find the minimum diameter in the Diameters array and then get the two radii corresponding to that diameter from the Radii array.  At this point it might be less work to use Yuri's distance map approach.  However, if all you need is an estimate of the size of the smallest inscribed circle, the Diameter, Min measurement would give you that directly without any extra computation.